Ruhelage

Rückstellkraft

Auslenkung

08-04 - Kettenpendel

Version Stand
29.11.2021
Andreas Jäger

Stand

Überstand

Ursache für die Rückstellkraft ist
die Gewichtskraft des (Ketten-)
Überstandes

Pause

Weiter

x1: 0
t: 0
x2: (x1 * cos(t))
NP: (0, 0)
P2: (0, x2)
D = 1.5 (slider from 0 to 1.5, step 0.5)
fRück: ((-D) * x2)
P3: (x1, 0)
a = false
b = false
d = false
P1: (0, x1)
o = false
v = Vector(NP - (1, 0), P2 - (1, 0))
u = Vector(P2 + (1, 0), P2 + (1, fRück))
c = Semicircle((0, -5), (-5, -5))
f = Segment((-5, -5), (-5, (-x2)))
h = Segment((0, -5), (0, x2))
i = Segment((-5, -5), (-5, 5))
j = Segment((0, -5), (0, 5))
e = Semicircle((-5, 5), (0, 5))
k = Circle((-2.5, -5), 2.5)
p = Circle((-2.471688957128558, 5), 2.5)
O1: (-2.5, 5) + (2.5 * (cos(x2), sin(x2)))
O2: (-2.5, 5) + (2.5 * (cos(x2 + π / 2), sin(x2 + π / 2)))
O3: (-2.5, 5) + (2.5 * (cos(x2 + (2 * π / 2)), sin(x2 + (2 * π / 2))))
O4: (-2.5, 5) + (2.5 * (cos(x2 + (3 * π / 2)), sin(x2 + (3 * π / 2))))
U1: (-2.5, -5) + (2.5 * (cos(x2 + (0 * π / 2)), sin(x2 + (0 * π / 2))))
U2: (-2.5, -5) + (2.5 * (cos(x2 + π / 2), sin(x2 + π / 2)))
U3: (-2.5, -5) + (2.5 * (cos(x2 + (2 * π / 2)), sin(x2 + (2 * π / 2))))
U4: (-2.5, -5) + (2.5 * (cos(x2 + (3 * π / 2)), sin(x2 + (3 * π / 2))))
l = Segment(O1, O3)
m = Segment(O4, O2)
n = Segment(U4, U2)
q = Segment(U1, U3)
Text1: "Rechtes Seilende " + (If[x2 < 0, "heruntergezogen", If[x2 > 0, "hochgezogen", "an Ruheposition"]]) + ""
ur = Segment((0, (-x2)), (0, x2))
ül = Segment((-5, (-x2)), (-5, x2))